In python:

I have this so far but not sure how to get it to work or incorporate the positive and negative equation to it.

def positive(value): if value > 0: return value if value < 0: return value * -1 else: return 0

def plusRoot(a, b, c): d = (b**2) - (4*a*c) solve1 = (-b + math.sqrt(d))/(2*a) solve2 = (-b - math.sqrt(d))/(2*a) return solve1, solve2

thenum = plusRoot(1, 2, 1) print(plusRoot)

Write a function called plusRoot that accepts three numbers (a,b,c). It should then find and return the root of the equation ax

2 + bx + c = 0 using the positive version of the

quadaratic formula: x1 =

b+b24ac 2a .

Then write the pair function called negRoot that accepts three numbers (a,b,c) and finds and prints the 2nd root using the negative version of the quadratic. x2 = b+b^24ac/2a.

Then in your main program show that you program works by finding the roots of the two equations below, catching the result and printing out the results.

1x^2 2x 35 = 0

Answers should be 7 and -5.

4x^2 24x + 35

Answers should be 2.5 and 3.5.