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In the ARMv 8 architecture, there are 3 1 general - purpose registers available for both 3 2 - bit ( W - type )

In the ARMv8 architecture, there are 31 general-purpose registers available for both 32-bit (W-type) and 64-bit (X-type) operations. These registers are addressed in machine instructions, which point to the specific registers being used. Considering the ARMv8 architecture, if a machine instruction is designed to point to one of the 32-bit W-type registers, and another instruction is designed to point to one of the 64-bit X-type registers, how many bits are required in each instruction to address the registers?

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