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In the below code of Python implementation of Regula Falsi Method, the equation in return variable should be taken as input. The code should work
In the below code of Python implementation of Regula Falsi Method, the equation in return variable should be taken as input. The code should work for any type of equation as here we could just update in return variable so it should be taken as user input. Kindly update the code.
Code:
import math def f(x): return 2*x*math.cos(2*x)-(x+1)*(x+1) def RegularFalsi(x0,x1,e): Iteration = 1 condition = True while condition: x2 = x0 - (x1-x0) * f(x0)/( f(x1) - f(x0) ) print('Iteration-%d' % (Iteration)) print('x2 = %0.6f and f(x2) = %0.6f'% (x2, f(x2))) if f(x0) * f(x2) < 0: x1 = x2 else: x0 = x2 Iteration = Iteration + 1 condition = abs(f(x2)) > e print(' Required root is: %0.8f' % x2) x0 = input('Enter Value of a: ') x1 = input('Enter Value of b: ') e = input('Tolerable Error: ') x0 = float(x0) x1 = float(x1) e = float(e) if f(x0) * f(x1) > 0.0: print('Given guess values do not bracket the root.') print('Try Again with different guess values.') else: RegularFalsi(x0,x1,e)
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