In the game of roulette, a player can place a $6 bet on the number 21 and have a E probability oi winning. It the metal ball lands on 21, the player gets to keep the $5 paid to play the game and the player is awarded an additional $210. Otherwise, the player is awarded nothing and the casino takes the player's 956. What is the expected value of the game to the player? if you played the game 1000 times, howr much would you expect to lose? The expected value is $ 1132'. (Round to the nearest cent as needed.) The player would expect to lose about $|:. (Round to the nearest cent as needed.)