In the gure here, a red car and a green car move toward each other in adjacent lanes and parallel to an x axis. At time t = 0, the red car is at x, = 0 and the green car is at xg = 214 m. If the red car has a constant velocity of 26.0 km/h, the cars pass each other at x = 43.3 m. On the other hand, if the red car has a constant velocity of 52.0 km/h, they pass each other at x = 76.4 m. What are (a) the initial velocity and (b) the (constant) acceleration of the green car? Include the signs. eTextbook and Media Assistance Used m Assistance Used Constant-acceleration equations. There are two pairs of data for a red-car speed and a passing point. For each pair, set up two simultaneous equations, one for each car. At the moment of passing, the cars have the same coordinate. Use that fact to merge the two simultaneous equations. Saphanation between furo cars = 214m Case - 1 . red can has velocity = 26 km / h = 26 *5 m s 18 - 7. 22 m/s And the cars meet / pass each orthen at x = 43:3 m time taken by red can in travelling 43.3m = 43.3 - 6 8 7. 22 Green can towells : 214 - 43.3 = 170.7m in 6 seconds , Let " initial velocity of green can e a - acceleration so and equation of motion . x = ut + 1 at2 170 . 7 = 6 4 + 1 xax 36 = ) 170 . 7 = 6 4 + 18 9 - 1 Case - 2 if Used = 5 2. 0 km/h = 14 . 44 m/s t = i - 76.4 14.4 4 So Green cann will travel = 214- 76-4 = 137-6m n = ut + " at2 - 137.6 = 5. 294 +1xax(s. 29)