In this part you need to figure out the orientation of the polarizer behind the orange curtain. You need to develop your own method of doing so using knowledge that you've acquired during this lab. To practice, you can try to check your answer to make sure that your method works. But for the lab report, please include screenshot of the orange curtain and your guess for the polarizer angle (do not click on "check your answer"). Describe your method and explain how it allows you to find the orientation of the hidden polarizer. (formulas given attached in picture)

Polarized light 0 X X + X I (W/m/m) Intensity vs. position 800 Scenarios: 1 ional Aid ... J IDEA Public Schools C... > > 600 Correct Answers 400 Incorrect Answers Your tutor is working Rate the answer on your answer 200 0 >x (cm) 0 5 10 15 20 25 30 35 40 Sics fifi Course: Add * incident light polarizer 1 polarizer 2 polarizer 3 1 = 800.0 W/m^2 1= 400.0 W/m^2 1 = ?? ? ? W /m^2 1 = 11.5 W/m^2 polarizer 1 = 113 degrees polarizer 3 = 0 degrees Send The goal is to figure out the angle of polarizer 2. When you know what polarizer 2 = 0 degrees it is, set the polarizer 2 slider to that value and then check your answer. Check your answer |Pick a new scenario + start again Orange curtains are used to cover up part of the graph and polarizer 2. Your goal is to determine the angle of the transmission axis of polarizer 2. Once you have figured it out, set the "polarizer 2" slider to that angle, and check your answer. If you're right, the curtains will be removed. If not, you can try again. Feel free to use the polarizer 1 and polarizer 3 sliders to adjust the angle of the transmission axes of those polarizers. (Note that the polarizer 2 slider does not adjust the angle of polarizer 2.) The graph shows the intensity of the light at different locations along the x axis. See how many different ways you can figure out the answer. 2:28 PM Type here to search O X W 96 F 8/3/2022One Polarization of Light_Revised_AC(1).pdf 0 X X + X E 2 of 4 Q + () from the second polarizer. ional Aid ... J IDEA Public Schools C... > > Polarizer #1 Polarizer #2 Polarizer #3 E1 X Unpolarized on Receive your E-field In solution Figure 4 Light transmitted through three polarizers The intensity after passing through the first polarizer is I, and the intensity after passing through the second polarizer, 12, is given by 12 = 1 cos . (2) o get helped ASAP The intensity after the third polarizer, 13, is given by 13 = 12 Cos2 (n/2 - 4) = 1, cos2 4 cos2(n/2 - $) = 1, (cos q sin )2, (3) question at a time since cos(n/2 - ) = sing. Using the trigonometric identity 2 sin o cos $ = sin 2, we get: all relevant information 13 = 4 sin2 2q. (4) We predict that the maximum intensity will be four times smaller than the max intensity for the mage to ask a question two-polarizer case and that intensity will run through its full cycle in x/2 radians rather than n fficult to type radians as was the case with two polarizers. Type here to search 3:44 PM 98.F A 8/3/2022