In working through your analysis, it is a great idea to copy$/$paste the following data. The coordinates are in m$.$ For example, xN is the x$-$coordinate of point N as seen from the OOO coordinate system. The weights are in N$.$ The values:

WC

WB

WS

WBU

correspond to the weights of the cab$/$chassis$,$ the boom, the stick, and the bucket$($w$/$dirt$),$ respectively. Here is your data:

xOOO$=0\mathrm{.}0000000$;

yOOO$=0\mathrm{.}0000000$;

xOO$=-2\mathrm{.}0000000$;

yOO$=1\mathrm{.}6610000$;

xO$=-1\mathrm{.}8350000$;

yO$=1\mathrm{.}6610000$;

xN$=-2\mathrm{.}0000000$;

yN$=1\mathrm{.}2680000$;

xA$=-1\mathrm{.}2330000$;

yA$=0\mathrm{.}9920000$;

xQ$=-3\mathrm{.}0000000$;

yQ$=0\mathrm{.}4060000$;

xS$=-1\mathrm{.}0000000$;

yS$=0\mathrm{.}4060000$;

xB$=-0\mathrm{.}2156064$;

yB$=3\mathrm{.}8661279$;

xC$=3\mathrm{.}4910562$;

yC$=4\mathrm{.}7360000$;

xD$=0\mathrm{.}6031774$;

yD$=4\mathrm{.}4739529$;

xJ$=0\mathrm{.}7101229$;

yJ$=3\mathrm{.}9387178$;

xE$=3\mathrm{.}6842832$;

yE$=5\mathrm{.}6154138$;

xF$=4\mathrm{.}2725195$;

yF$=4\mathrm{.}3813111$;

xG$=3\mathrm{.}9978475$;

yG$=2\mathrm{.}0634006$;

xK$=3\mathrm{.}9576754$;

yK$=3\mathrm{.}9439952$;

xH$=4\mathrm{.}5572911$;

yH$=1\mathrm{.}6681185$;

xI$=4\mathrm{.}2126102$;

yI$=1\mathrm{.}1288643$;

xL$=4\mathrm{.}0467304$;

yL$=1\mathrm{.}5846152$;

xM$=3\mathrm{.}5855209$;

yM$=1\mathrm{.}0974953$;

WC$=110166\mathrm{.}3000000$;

WB$=20012\mathrm{.}4000000$;

WS$=9280\mathrm{.}2600000$;

WBU$=5395\mathrm{.}5000000$;

For the above bucket FBD$,$ write the static force balance equations and determine the loads at the L$,$ I pins: $L_x,L_y,F_{HI}.$ Declare whether the binary link $F_{HI}$ is in tension or compression. The answer choices for Link F$\_($HI$)$ is in either $(1)$ tension $(2)$ compressed or $(3)$ unloaded