Question
Independent random samples of professional football and basketball players gave the following information. Assume that the weight distributions are mound-shaped and symmetric. Weights (in lb)
Independent random samples of professional football and basketball players gave the following information. Assume that the weight distributions are mound-shaped and symmetric. Weights (in lb) of pro football players: x1; n1 = 21
246 | 262 | 256 | 251 | 244 | 276 | 240 | 265 | 257 | 252 | 282 |
256 | 250 | 264 | 270 | 275 | 245 | 275 | 253 | 265 | 271 |
Weights (in lb) of pro basketball players: x2; n2 = 19
203 | 200 | 220 | 210 | 193 | 215 | 222 | 216 | 228 | 207 |
225 | 208 | 195 | 191 | 207 | 196 | 183 | 193 | 201 |
(a) Use a calculator with mean and standard deviation keys to calculate x1, s1, x2, and s2. (Round your answers to one decimal place.)
x1 = | |
s1 = | |
x2 = | |
s2 = |
(b) Let 1 be the population mean for x1 and let 2 be the population mean for x2. Find a 99% confidence interval for 12. (Round your answers to one decimal place.)
lower limit | |
upper limit |
(c) Examine the confidence interval and explain what it means in the context of this problem. Does the interval consist of numbers that are all positive? all negative? of different signs? At the 99% level of confidence, do professional football players tend to have a higher population mean weight than professional basketball players?
Because the interval contains only negative numbers, we can say that professional football players have a lower mean weight than professional basketball players.Because the interval contains both positive and negative numbers, we cannot say that professional football players have a higher mean weight than professional basketball players.Because the interval contains only positive numbers, we can say that professional football players have a higher mean weight than professional basketball players.
(d) Which distribution did you use? Why?
The Student's t-distribution was used because 1 and 2 are known.The standard normal distribution was used because 1 and 2 are unknown.The standard normal distribution was used because 1 and 2 are known.The Student's t-distribution was used because 1 and 2 are unknown.
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