Index of refraction for a square of glass: You shine a laser beam on the surface of a square of glass, collecting the following information: $n_2=1,p=10\mathrm{.}0+-0\mathrm{.}2cm,q=-6\mathrm{.}6+-0\mathrm{.}2cm.$ Complete the calculation of the index of refraction of the glass $(n_1)$ using

$\frac{n_1}{p}=-\frac{n_2}{q}$

as well as the uncertainty in the index of refraction using the calculus method. Output your answer to the correct number of decimal places.

$[]$ import numpy as np

# Calculate the index of refraction $n1$ as well as its uncertainty

n$2=1\mathrm{.}0$ # index of refraction of air

$p=10\mathrm{.}0$#$cm$

punc $=0\mathrm{.}2$#$cm$

$q,=-6\mathrm{.}6$#$cm$

qunc $=0\mathrm{.}2$#$cm$

# Add code below to calculate $n1$ and the uncertainty in $n1$ using

# the calculus method. The print function assumes that the index

# of refraction of glass is stored in a variable called $n1$ and

# its uncertainty in a variable called n$1$unc.

# Modify the print statement so the correct number of digits is output