Initial position : t= 0s Final position : t = 25s Answer: a) 220 m/s b) 2464.3 m c) 179.5 m/s

- You are tasked to design such a flight path which mult meet the following . start your parabolic path by pointing the aircraft 450 above me horizontal . Follow a free fall trajectory for 25 seconds . At the end of the 25seconds, your plane should be heading no more than 300 below the horizontal so that you have time to pull up and not crash the ground . Vo 1 t - 25 5 busolo It os a) what speed ( magnitude of velocity ), in mys should you have when you are 450 above the horizontal at the start ? b ) what is the maximum height you would achei've above your starting point ? ( ) what speed, in mil, will you have when you are pointing 30 0 below the horizontal at the end ? ay # - 9.81 m / 2 Vo = Vo cos ( us o ) Vo sin (US) VE V. at V S = N $ cos ( 30 9 ) m/s Nf sin (3OP ) magnitude