Input signal x[n] and impulse response h[n] are given. xnmu[n]. h[n]=(0.3) n uni: where X(z)=z/cz-1): H(2)=2/(2-0.5) Using z transform and Y(2)=X(2)H(z) find Y(2) and then yin). Which of the followings is y(n) signal a. y(n) = u(n)(1-2(0.5) ) 0 b. y[n] = U[n] 1+2 - 5 n) O cyn] = unic(-0.5Yn-2-1)n) O d.y[n] = unK2-(0.5n) O ey[n] = u(nI((-0.5)^n -2)