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INSERTION-SORT(A): 1 For j = 2 to A.length 2 Key = A[ j ] 3 //inser A[ j ] into the sorted sequence A[1...j-1] 4
INSERTION-SORT(A):
1 For j = 2 to A.length
2 Key = A[ j ]
3 //inser A[ j ] into the sorted sequence A[1...j-1]
4 i=j-1
5 while i > 0 and A[ i ]>key6
6 A[i+1] =A[ i ]
7 i=i-1
8 A[i+1]=key
Observe that while loop of line 5-7 of the insertion-sort uses linear search to scan through the sorted subarray A[i...j-1].Can we use a binary search instead to improve the overall worst case running time of insertion sort to (n ln n)? (Justify your answer)
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