Instructions are on the photo.

Use the following graph and table to answer the questions below Column 1 Column 2 Column 3 Column 4 Weight over block Normal force (N) Mass over the Static friction (N) (grams) weight carrier 0 35 0.343 20 0.196 45 0.441 40 0.392 59 0.578 60 0.588 60 0.588 80 0.784 65 0.637 100 0.98 74 0.725 Friccion estatica vs Fuerza normal F.. = (0.3656N/N)FN + 0.372N 0.8 0.7 0.6 0.5 Frs (N) 0.4 0.3 0,2 0.1 0.2 0.4 0.6 0.8 1 1.2 FN (N) 1. The profile or shape of the previous graph is: 2. The profile or shape of the previous graph is due to: a. that friction is directly proportional to the normal force b. that acceleration is inversely proportional to the force of friction c. that acceleration is directly proportional to the total mass d. that the normal force is directly proportional to the friction force e. none of the above and/or below 3. To overcome the force of Static Friction, and make the object move, it must move with: a. it is not possible to answer correctly b. constant acceleration c. constant friction force d. constant total mass e. constant velocity 4. What physical quantity does the slope represent