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Instructions from your teacher: Complete the same static method of the Problem class. There are 3 string parameters: x, y, z. The method returns true
Instructions from your teacher: Complete the same static method of the Problem class. There are 3 string parameters: x, y, z. The method returns true if the string y occurs the same number of times in string x as string z occurs in x. La Main.java Problem.java: 1 import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scan = new Scanner( system.in); System.out.println("Enter a string:"); String a = scan.nextLine(); a = a.toLowerCase(); System.out.println("Enter a string:"); String b = scan.nextLine(); b = b.toLowerCase(); System.out.println("Enter a string:"); String c = scan.nextLine(); C = c.toLowerCase(); 2 3 4 - 5 6 - 7 8 9 10 11 12 13 14 15 16 17 Here is a sample run: Enter a string: nothing there Enter a string: th Enter a string: n true It prints true at the end because "th" appears twice in "nothing there and n appears twice in "nothing there" as well. // call the same method and print the returned value. Complete the count method and use this is completing the same method. Do not count overlapping strings. For example, if c = "RRR" and d = "RR" then the method should return 1. java version "1.8.0_31" Java (TM) SE Runtime Environment (build 1. 8.0_31-b13) Java HotSpot (TM) 64-Bit Server VM (build 25. 31-b07, mixed mode) ? Complete the main method and test your solution prior to submitting. (5 points) Main.java Problem.java: public class Problem { private Problem() { } public static boolean same string x, String y, string z ) { return true; } 1* count returns the number of times string d appears in string c. DO NOT count overlapping strings. */ public static int count( String c, String d ) { return 0; } }
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