Question: 3 The value of TT can be approximated by using the following series: = 41 4(1 3 + 2n - 1 2n + 1

3 The value of TT can be approximated by using the following series:  = 41 4(1 3 + 2n - 1 2n + 1 The program 1 #include 2 #include 3 4 using namespace std; 5 6 int main() 7 { 8 9 10 13 14 16 69 18 19 20 22 23 25 2626 27 28 29 } cout < < endl < <

3 The value of TT can be approximated by using the following series: = 41 4(1 3 + 2n - 1 2n + 1 The program in main.cpp uses this series to find the approximate value of T. However, the statements are in the incorrect order, and there is also a bug in this program. Rearrange the statements and remove the bug so that this program can be used to approximate 7. 1 #include 2 #include 3 4 using namespace std; 5 6 int main() 7 { 8 9 10 13 14 16 69 18 19 20 22 23 25 26 double pi = 0; long i; long n; cin >> n; cout < < "Enter the value of n: "; cout < < endl; if (i % 2 == 0) pi else pi + (1 / (2 * i + 1)); pipi (1 / (2 * i + 1)); for (i = 0; i < n; i++) { } pi = 0; pi= 4pi; 26 27 28 29 } cout < < endl < < "pi = " < < pi < < endl; return 0;

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