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int main(int argc, char *argv[]){ : : printf(Enter a first integer> ); if (readInt(&n1)) printf(You enetered %d , n1); else printf(Wrong input ); printf(Enter a
int main(int argc, char *argv[]){
:
:
printf("Enter a first integer> "); if (readInt(&n1)) printf("You enetered %d ", n1); else printf("Wrong input "); printf("Enter a secnd integer> "); if (readInt(&n2)) printf("You enetered %d ", n2); else printf("Wrong input "); printf("the sum of %d and %d is %d ", n1, n2, n1+n2); exit(0); }
Using only the standard input/output function fgetc(), define a C function, called int readInt(int *value), that reads an integer from the keyboard (stdin), stores it in *value and, returns 1 for success or 0 for fail (in case the user enters nondigit characters). In particular, readInt() reads all characters, one by one, until a blank (or newline) is encountered. The string is then converted to an integer. It is also possible to have the sign charcater (+/-) precedding the number. Notes: . You need also to define a main() function that should look like the following one: int main(int argc, char *argv[]) { printf ("Enter a first integer> "); if (readInt (&nl)) printf("You enetered %d ", nl); else printf ("Wrong input "); printf ("Enter a secnd integer> "); if (readInt (&n2)) printf ("You enetered %d ", n2); else printf ("Wrong input "); printf("the sum of %d and %d is %d ", nl, n2, n1+n2); exit(0); Do not use any other function from the input/output standard library, and the string-to-integer conversion should be done using ASCII codes and multiplcations by 10Step by Step Solution
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