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int unorderedSearch ( const T a [ ] , unsigned n , const T& x ) / / Look for x within an unsorted array

int unorderedSearch (const T a[], unsigned n, const T& x)
// Look for x within an unsorted array a, containing n items.
// Return the position where found, or -1 if not found.
{
int i;
for (i =0; ((i < n) && (a[i]!= x)); i++) ;
if (i >= n)
i =-1;
return i;
}
Suppose that we have arranged the items in our array so that ones most often searched for occur near the beginning of the array. Specifically, assume that: we only search for "x" values that really are in the array "a", and the probability of any particular search being for the element a[i] is c/(2i).
What is the average case complexity of unorderedSearch for this input distribution? (Show your work).

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