Interpret data below.

33. A home health company identified individuals who received services that would benefit from a weight management program. The service was offered to all clients. After 12 months of implementation, the data analysis department ran a statistical analysis to determine if there were differences between BMIs based on race (Black/African American, Hispanic/Latino, and White/Caucasian). Identify on the printout which values you would interpret by highlighting them. Write up the findings of your interpretation (6 points). Oneway Descriptives Calculated BMI 95% Confidence Interval for Mean N Mean Std. Deviation Std. Error Lower Bound Upper Bound Minimum Maximum Black/African 23 25.8549 4.22775 .88155 24.0267 27.6831 21.32 36.00 American Hispanic/Latino 22 22.7150 2.74766 58580 21.4968 23.9333 18.78 31.70 White/Caucasian 21 24.0096 1.99709 43580 23.1006 24.9187 21.45 28.56 Total 24.2211 3.38269 41638 23.3896 25.0527 18.78 36.00 Test of Homogeneity of Variances Levene Statistic df1 df2 Sig. Calculated BMI Based on Mean 5.180 .184 IN Based on Median 2.391 N 53 100 Based on Median and with 2.391 44.383 103 adjusted of Based on trimmed mean 4.336 2 63 .017 ANOVA Calculated BMI Sum of Squares dit Mean Square F Sig Between Groups (Combined) 112.233 2 56.117 5.598 .006 Linear Term Unweighted 37.377 37.377 3.729 .058 Weighted 40. 180 40.180 4.008 .050 Deviation 72.053 1 72.053 7.188 009 Within Groups 631.535 63 10.024 Total 743.768 65 Post Hoc Tests Multiple Comparisons Dependent Variable: Calculated BMI Mean 95% Confidence Interval Difference (1- (1) race (J) race Std. Error Sig. Lower Bound Upper Bound Tykey HSD Black/African Hispanic/Latino 3.13985 94419 .004 8735 5.4062 American White/Caucasian 1.84525 95561 138 -.4485 4.1390 Hispanic/Latino Black/African -3.13985 94419 004 -5.4062 .8735 American White/Caucasian -1.29460 96592 378 -3.6131 1.0239 White/Caucasian Black/African -1.84525 .95561 .138 -4.1390 1485 American Hispanic/Latino 1.29460 .96592 378 -1.0239 3.6131 *. The mean difference is significant at the 0.05 level