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(Inverse Functions) The cost, in millions of dollars, to remove x% of a pollutant from a lake can be 36x 100-x interpretation. Note that values

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(Inverse Functions) The cost, in millions of dollars, to remove x% of a pollutant from a lake can be 36x 100-x interpretation. Note that values are rounded to 2 decimal places where necessary. approximated by the function C = f(x) = . Determine the value of f~'(24) and give a practical (A) f7'(24)=40. The cost to remove 24% of the pollutant is $40 million. (B) f7'(24)=40. The cost to remove 40% of the pollutant is $24 million. (C) f7'(24)=11.37. The cost to remove 24% of the pollutant is $11.37 million. D) 1 (24) =11.37. The cost to remove 11.37% of the pollutant is $24 million

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