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ions of arsenic are present in 1 mL of that 10C, low potency, dilution of pure arsenic trioxide?10^-23 (ions/mL) concentration of a 30C, standard potency,



ions of arsenic are present in 1 mL of that 10C, “low potency,” dilution of pure arsenic trioxide?10^-23 (ions/mL)

concentration of a 30C, standard potency, arsenicum album remedy: 10^-60 ion/ltr

ions of arsenic are present in 1 mL of that 30C, standard potency, arsenicum album remedy:10^-63 Ion/mL

1.Obviously one cannot have a fraction of an atom in a sample. But if you take the concentration, which is in units of moles/liter, and take its inverse, you get liters per mole, which is the volume necessary to have one mole of solute. If you then divide that quantity by Avogadro’s number, you get liters per molecule (or atom), which is the volume necessary to have one molecule of solute. What volume (in liters) of homeopathic 30C arsenicum album would you need to have one ion of arsenic?

2.Your answer to question 1  should be large enough that it is extremely hard to visualize, so we will do a little work to try to understand it. First, convert that volume to cubic kilometers.

3.Clearly we are going to have to go to astronomical sizes to visualize this. It is tempting to try to make it a sphere centered on the sun, but unfortunately that introduces some mental bias, because nothing in our experience is that big in three dimensions. So instead let’s look at it like a squashed cylinder, as shown below. We’ll make the depth of the cylinder the diameter of the Earth (12,742 km), figure out what its radius is, and visualize the cylinder as centered on the sun. The volume of a cylinder is πr2d. What is the radius of this cylinder with the same volume that you find in question 2

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