Is this correct? Calculations written in purple are the calculations I did.

1.A survey was taken asking all participants for their heights in inches. Complete the following table which you will use for questions 2 & 3.

Class Frequency Midpoint (Xm) X - f . Xm f . X- 58-61 58+61)/2=59.5 59.52 = 3,540.25 2* 59.5 = 119 2* 3540.25=7080.5 62-65 (62+65)/2=63.5 63.52 = 4032.25 6 * 63.5 = 381 6 * 4032.25 = 24193.5 66-69 66+69)/2=67.5 67.52 = 4556.25 9 *67.5 = 607.5 9 * 4556.25 = 41006.25 70-73 (70+73)/2=71.5 71.52 = 5112.25 8 * 71.5 = 572 8 *5112.25 = 40898 74-77 (74+77)/2=75.5 75.52 = 5700.25 1 * 75.5 = 75.5 1 * 5700.25 = 5700.25 Total= Total=&f Xm=1,755 [f*Xm?= 118,878.5 n = 26 2. Find the modal class, and the mean for the grouped data. Round the mean to the nearest tenth (one decimal place). 1,755 Modal Class: 66 - 69 Mean = X = If*Xm = 67.5 n 26 Mean: 67.5 3. Find the sample variance and standard deviation for the grouped data. Round the variance and standard deviation to the nearest tenth (one decimal place). Variance = $2 = n(EX? )-(2X)= = 26 (118,878.5)-1,7552 = 16.6 n (n-1) 26 (26-1) Standard Deviation = S = V16.6 = 4.1