Is this correct? Thank you

EXTRA CREDIT!!! Fritz Haber once attempted to pay for Germany's WWI reparation debt by developing a method of extracting gold from sea water. Gold is indeed present in ocean water but only in minute quantities it varies, but can be as high as 44ppb (parts per billion), which is equivalent to 0.0000044% mass percent. If gold is valued at $62.77 per gram, assuming the there are 44109 grams gold per gram seawater and the density of ocean water is 1.007grams/mL, what volume of ocean water, in liters, would be required to pay off Germany's war debt - $270,000,000,000 ! This question is worth 5 extra credit points. Show your calculations for this problem! Edit View Insert Format Tools Table 12pt Paragraph BIT2