Is this correct?

Two digits are to be chosen at random, one after the other, from the ten digits, without repetition, to form a 2-digit number. Let E1 and E2 be the events that the first digit is even and the second digit is even respectively. Express the following probabilities in terms of these events using probability notations and compute them accordingly. i. Both the first and second digits are even P(E1E2)=P(E1)P(E2E1)=(21)(94)=92 the probability of the first and second digits being even is 92. ii. The second digit is odd. 1P(E2)=194=95 the probability of the second digit being odd is 95. iii. One digit is odd. P(E1E2)=1P(E1E2)=1P(E1)P(E2E1)=1(21)(94)=95 the probability of one digit being odd is 95