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=> I(t) = 1(1) =1 =1 =0 Solutions are: q (t) = Cf ,+ C, expl-(f + f, )] 9, (t ) = Cf -C,
=> I(t) = 1(1) =1 =1 =0 Solutions are: q (t) = Cf ,+ C, expl-(f + f, )] 9, (t ) = Cf -C, expl-(f, + f, )+ ] (9 Where C, & C, are related to the initial conditions by: (t=0) => exp(0)=1 9 , ( 0 ) + 9, ( 0) = C, ( f 12 + f 21) C = 9, (0) + 92 (0) 12 + $ 21 9, (0) - q, (0) = C,(f 12 -f21)+ 202 C, = (9, (0) -q, (0))
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Counting With Symmetric Functions
Authors: Jeffrey Remmel, Anthony Mendes
1st Edition
3319236180, 9783319236186
