It is desired to evaporate 13.1 lb of ethanol with a stream of dry air. The pressure remains constant at 738 mm Hg and the temperature is 20C. The outlet pressure of the air-ethanol mixture is 738 mm Hg. The vapor pressure of ethanol is 44.5 mm Hg at a temperature of 20 C.

What volume of dry air is needed to evaporate ALL the ethanol? How many moles of ethanol are there? What is the ratio of lb-mol of dry air / lb-mol of ethanol in the mixture? What is the mole fraction of ethanol in the dry air-ethanol mixture?