It takes 1 nanosecond (1 x 10-9 s) to move a word from L1 cache to the registers and 10 nanoseconds to move a word from L2 cache to the registers. Assuming that all of the words that are not in L1 cache are in L2 cache, what is the percentage reduction in the time it takes to get the 2,000 words of data into the registers if the hit rate is increased from 95% to 97%? Round your answer to the nearest tenth of a percent. Hint: Start by calculating the time to load the words available from L1 cache plus the time to load those from L2 cache, for each hit rate.