I've been trying to figure this out but here's the hw help provided:a) here we can just use constant speed kinematics, since the manager will measure tm=L/v. Don't forget to convert to nanoseconds.b) answered c) both space cars will measure a time for themselves ?(t0) that is shorter than the manager's time because the manager's time is dilated, (T=yTo), and shorter than the time they measure for the other space car. To find the time that each space car measures for the other car, you would need to find the velocity additional formula, u' = { u+v/1+(uv/c^2) } and then use that velocity to calculate Larenz's factor, gamma and dilated time. T=yT0d) answered e) to find the time that the rival measures for the car moving in the sink direction you would need to use the velocity subtraction formula, u'= {u-v/1-(uv/c^2) } PLEASE PROVIDE ANSWERS AND EXPLANATIONS ?

oo An interstellar race manager (M) is trying to compare the performance of two new spacecar models. Two flags are set up 'S d = 31.5 m to the right and left of the manager. Spacecar A comes from the left, and spacecar B comes from the right. To the % manager, the two spacecars appear to pass the flags at the same instant and then pass by her simultaneously a moment later. She _\"_%then determines that the speed of both spacecars is v = 0.650c. vV v =N dd Macm 'What time tp did she measure for each car to travel from the flag to her position? 486.4 I, = ns Incorrect According to the driver of spacecar B, which of the spacecars went from the flag to the manager in less time? - & () They tied. According to the driver of spacecar B, how long 7, did it take? 301.68 A= Incorrect A rival team's spacecar observes all of this while speeding by from right to left at 0.906 with respect to the manager. According to this rival observer, which of the spacecars went from the flag to the manager in less time? () They tied. ~ A According to the rival observer, how long # did it take? 242.95 fc = ns Incorrect