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Java binary search tree Add the following comparison method to the binary search tree class created in class. This method should compare two tree objects

Java binary search tree Add the following comparison method to the binary search tree class created in class. This method should compare two tree objects to see if they are visually identical (have nodes in the exact same positions, value doesn't matter). Recursion and a helper method may be useful in solving this. Method header: public boolean visuallyIdentical(MyBinarySearchTree rhs)

=================================code================================

public class BinarySearchTree> {

private Node root;

public BinarySearchTree()

{

root = null;

}

public void printTree()

{

printTree(root);

}

private void printTree(Node current)

{

if(current != null)

{

String content = "Current:"+current.data.toString();

if(current.left != null)

{

content += "; Left side:"+current.left.data.toString();

}

if(current.right != null)

{

content += "; Right side:"+current.right.data.toString();

}

System.out.println(content);

printTree(current.left);

printTree(current.right);

}

}

public void printInOrder()

{

System.out.print("In order:");

printInOrder(root);

System.out.println();

}

private void printInOrder(Node current)

{

if(current != null)

{

printInOrder(current.left);

System.out.print(current.data.toString()+",");

printInOrder(current.right);

}

}

public boolean contains(E val)

{

Node result = findNode(val, root);

if(result != null)

return true;

else

return false;

}

private Node findNode(E val, Node current)

{

//base cases

if(current == null)

return null;

if(current.data.equals(val))

return current;

//recursive cases

int result = current.data.compareTo(val);

if(result < 0)

return findNode(val, current.right);

else

return findNode(val, current.left);

}

public E findMin()

{

Node result = findMin(root);

if(result == null)

return null;

else

return result.data;

}

private Node findMin(Node current)

{

while(current.left != null)

{

current = current.left;

}

return current;

}

public E findMax()

{

Node current = root;

while(current.right != null)

{

current = current.right;

}

return current.data;

}

public void insert(E val)

{

root = insertHelper(val, root);

}

public Node insertHelper(E val, Node current)

{

/* for showing steps to insert a given value

if(val.equals(9) && current != null)

{

System.out.println(current.data);

}

*/

if(current == null)

{

return new Node(val);

}

int result = current.data.compareTo(val);

if(result < 0)

{

current.right = insertHelper(val, current.right);

}

else if(result > 0)

{

current.left = insertHelper(val, current.left);

}

else//update

{

current.data = val;

}

return current;

}

public void remove(E val)

{

root = removeHelper(val, root);

}

private Node removeHelper(E val, Node current)

{

if(current.data.equals(val))

{

if(current.left == null && current.right == null)//no children

{

return null;

}

else if(current.left != null && current.right != null)//two children

{

Node result = findMin(current.right);

result.right = removeHelper(result.data, current.right);

result.left = current.left;

return result;

}

else//one child

{

return (current.left != null)? current.left : current.right;

}

}

int result = current.data.compareTo(val);

if(result < 0)

{

current.right = removeHelper(val, current.right);

}

else if(result > 0)

{

current.left = removeHelper(val, current.left);

}

return current;

}

private class Node

{

E data;

Node left, right;

public Node(E d)

{

data = d;

left = null;

right = null;

}

}

}

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