Java:

Create a path for a mouse to travel in a maze. Use a 2 dimensional array and start the mouse in location array[0][0]. The mouse must find its way to the opposite corner. Repeatedly get a random number representing one of 8 possible moves. A legal move is one that moves forward, does not run off the edge of the maze and does not land on a previous move. If the move is illegal the poor mouse must starts over with location [0][0]. Going forward is defined as the sum of the two array indexes either increasing or staying the same.

With each safe mouse move introduce a cat that may eat the mouse. The cat is a block of 4 maze locations forming a square. With each safe move made by the mouse create a cat. The random number generator generates a location that serves as the upper left corner location of the cat. The random number is dependent on the size and shape of the maze when the maze is first created. If the cat catches the mouse the mouse must begin again. Think through the operations I have described and make those operations methods that can be called in order to accomplish the cat aspect of the problem. I used four small methods to implement the cat part of the project.

Allow the mouse to repeatedly run the maze and choose the size of the two dimensional maze.

The output consists of three numbers.

The first is the number of times the mouse must start over before he finds a path from beginning to the end,

the second is the number of times he falls off the maze and

the third is the number of times the cat catches the mouse.

Then print the array to the screen showing the path that was successful and the last cat position. (HINT: use a two dimensional integer array, record the cat as 4 negative ones in the maze. When you print out the maze replace a -1 with the char C.)