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L1={x {0,1}| #1(x) is odd} L2={x {0,1}| x contains 11} (e) (10 points) Prove that Ls = { 1 {0,1}* | #1 (2) is odd
L1={x {0,1}| #1(x) is odd}
L2={x {0,1}| x contains 11}
(e) (10 points) Prove that Ls = { 1 {0,1}* | #1 (2) is odd and x does not contain 11 } is regular by constructing a product machine from Lj and L
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