Lab $12$:

Write a program that keeps track of daily sales of $10$ stores in an array

and determine

a$)$ Highest sale and the store number $($assume that the first store has the store number zero$)$

b$)$ Lowest sale and the store number

c$)$ Average sale No need to loop to take input multiple times.

input are in order:

$10987654321$

output needs to be:

Enter $10$ sales numbers:

Highest sales: $1$

Lowest sales: $10$

Average sales: $5\mathrm{.}5$

please help fix my program to pull the last number as the highest number and the first as the lowest number.

#include

#include

#include

using namespace std;

int main$()$

$\{$

$//($a$)$ Array to be searched $-$ list

$//($b$)$ Number of elements in the array $-$ length

$//($c$)$ Item that we are searching $-$ searchItem

const int size $=10$;

int value$[$size$]=\{1,2,3,4,5,6,7,8,9,10\}$;

int index $=0$;

double location $=-1$;

bool found $=$ false;

int searchItem $=0$;

cout $<<$ "Enter $10$ sales numbers:";

do$\{$

cin $>>$ value$[$index$]$;

index$++$;

$\}$while$($index $<$ size$)$;

while $($location $==-1$ && index $<$ size$)\{$

if $($value$[$index$]==$ searchItem$)\{$

location $=$ index;

index$++$;

$\}$

$\}$

if $($found$)\{$

double highestStoreNumber, lowestStoreNumber;

highestStoreNumber $=$ index;

lowestStoreNumber $=$ index;

$\}$

double highestStoreNumber $=\{10\}$;

double lowestStoreNumber $=\{1\}$;

double total $=0$;

double average;

for $($int i $=0$; i $<$ size; i$++)\{$

if $($value$[$i$]>$ highestStoreNumber$)$

highestStoreNumber $=$ value$[$i$]$;

if $($value$[$i$]<$ lowestStoreNumber$)$

lowestStoreNumber $=$ value$[$i$]$;

total $+=$ value$[$i$]$;

$\}$

average $=$ total $/$ size;

cout $<<$ "Highest sales: $"<<$ highestStoreNumber $<<$ endl;

cout $<<$ "Lowest sales: $"<<$ lowestStoreNumber $<<$ endl;

cout $<<$ "Average sales: $"<<$ average $<<$ endl;

return $0$;

$\}$ number