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The Maclaurin series for f(a ) = sin(x ) is ( - 1)"(x )27+1 .3 ac = + + ... n= (2n + 1)! 3! 5! 7! sin(11x) By transforming the series for sin(x), find the first 4 nonzero terms of the Maclaurin series for TX = 1331 11 161051 19487171 + 6 + 120 5040 26 v + . Written compactly, this series is T(ac) = (-1)2 . 112n+1. x2n (2n + 1)! Using your new series lim T(ac) = sin (11x) X x-0