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LEARNING UNIT 1 Particle TechnologyPresentation III EXAMPLE 1 4 2 2 0 5 0 0 0 . 0 2 0 5 9 9 0 .

LEARNING UNIT 1 Particle TechnologyPresentation III EXAMPLE 142205000.0205990.040.086990.070.218530.120.4410030.190.6812040.320.8814050.5116760.820571 Size d (m) EXAMPLE100grams of a random mixture consists of two components A and B inproportions 60% and 40% by mass, respectively. The particles are spherical(=1)andAandBhaveparticledensities500kg/m3and700kg/m3, vrespectively. The cumulative undersize mass distributions of the two components are shown in the table below:XA [FA (x)]XB [FB (x)]For component A1. Determinethenumberofparticlesineachfractionandthetotalnumberof particles of A in100grams of the mixture.2. Calculate the following statistical mean diameters (a) Arithmetic; (b) Length; (c) Surface; (d) Volume; (e) Square root; (f) Cube root and (g) Harmonic3. DrawaDifferentialCumulativeDistributionCurvedeterminethemedian SOLUTIONFirst, we estimate the number of particles per unit mass of A and B, by converting the size distributions into differential frequency number distributions and using:mass of particles number of particles mass of one =\times in each size range in size range particle 3 davgi mi =Ni \times v P xi 3 davgi mi = Ni \times P - forasphericalparticle 6where is the particle density and dis the arithmetic mean of Pavg adjacent sieve sizes. 3512849 kg \times \times (0.6\times 100g)NAkg 1000g (100g mix)=210771 N= iN=16(x ) i3 d P avg6(0.2)63(500)(1866.5\times 10)N =117484particles/kg 1Ni1174843134493097223695373345694087114191974604247797563512849210771xi0.20.30.180.130.070.050.030.020.021Mean size of range davg (m)1866.51540.51304.51103.5928776649549.5461Total (particles per kg)Particles A in 100g mixture x1=10.8=0.2 x2=0.80.5=0.3 davg =0.5x(2057+1676)=1866.5SOLUTION cont...A particles: .t n o cm m m m m m3 m 4.15.92.42.73.6.87.6683012534920117=1=1=1==R == DA DL Ds Dv DS RC DH D121325285909109010101010210951099301481111111414481\times 2\times \times \times \times \times \times \times 8\times 82\times 621564620264480262102115100.31.0.8.1.1.8.41.5328.5339.3333353334 N492791746Ni84427356517912457O739948909I : 113036330414647T sU elcit )5555L r m(.6.0.4.38695.91O ap 684503012746-g 1111976454vaS Ad N/d6.294E+012.035E+022.374E+023.349E+023.605E+025.267E+026.459E+028.379E+021.691E+034.901E+03 Nxd41.426E+181.765E+188.969E+175.480E+172.481E+171.482E+177.437E+164.198E+163.522E+165.184E+18 Nxd37.639E+141.146E+156.876E+144.966E+142.674E+141.910E+141.146E+147.639E+137.639E+133.820E+15 Nxd24.093E+117.439E+115.271E+114.500E+112.881E+112.461E+111.766E+111.390E+111.657E+113.146E+12 Nxd2.193E+084.829E+084.040E+084.078E+083.105E+083.172E+082.721E+082.530E+083.595E+083.026E+09 Ni1174843134493097223695373345694087114191974604247797563512849davg -(m)1866.51540.51304.51103.5928776649549.5461 SUM SOLUTION cont... F X10.80.50.320.190.120.070.040.020davg -(m)20571696140512041003853699599500422 SOLUTION cont...Median 1405m10.90.80.70.60.50.40.30.20.1002004006008001000120014001600180020002200Differential Cumulative Distribution Curved in m 42205000.0205990.040.086990.070.2185

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