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LEARNING UNIT 1 Particle TechnologyPresentation III EXAMPLE 1 4 2 2 0 5 0 0 0 . 0 2 0 5 9 9 0 .
LEARNING UNIT Particle TechnologyPresentation III EXAMPLE Size d m EXAMPLEgrams of a random mixture consists of two components A and B inproportions and by mass, respectively. The particles are sphericalandAandBhaveparticledensitieskgmandkgm vrespectively. The cumulative undersize mass distributions of the two components are shown in the table below:XA FA xXB FB xFor component A Determinethenumberofparticlesineachfractionandthetotalnumberof particles of A ingrams of the mixture Calculate the following statistical mean diameters a Arithmetic; b Length; c Surface; d Volume; e Square root; f Cube root and g Harmonic DrawaDifferentialCumulativeDistributionCurvedeterminethemedian SOLUTIONFirst, we estimate the number of particles per unit mass of A and B by converting the size distributions into differential frequency number distributions and using:mass of particles number of particles mass of one times in each size range in size range particle davgi mi Ni times v P xi davgi mi Ni times P forasphericalparticle where is the particle density and dis the arithmetic mean of Pavg adjacent sieve sizes. kg times times times gNAkg g g mix N iNx i d P avgtimes N particleskg NixiMean size of range davg mTotal particles per kgParticles A in g mixture x x davg xSOLUTION cont...A particles: t n o cm m m m m m m R DA DL Ds Dv DS RC DH Dtimes times times times times times times times times times NNiOI : T sU elcit L r mO ap g vaS Ad NdEEEEEEEEEE NxdEEEEEEEEEE NxdEEEEEEEEEE NxdEEEEEEEEEE NxdEEEEEEEEEE Nidavg m SUM SOLUTION cont... F Xdavg m SOLUTION cont...Median mDifferential Cumulative Distribution Curved in m
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