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Let f : R - R, f E C2 such that f'(a) = 0 and f(a) # 0. Prove that h : R2 -> R

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Let f : R - R, f E C2 such that f'(a) = 0 and f"(a) # 0. Prove that h : R2 -> R defined by h(x, y) : = f(x ty) - f(x - y) has a saddle point at (a, 0). Hint: A saddle point means we can find a direction from such point such that f 0

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