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Let f(x) = 12x + 11 - 3e^x. Then the equation of the tangent line to the graph of f(x) at the point (0,8) is
Let f(x) = 12x + 11 - 3e^x. Then the equation of the tangent line to the graph of f(x) at the point (0,8) is given by y = mx + b form=b =
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Nonlinear Optics And Photonics
Authors: Guang S He
1st Edition
019100734X, 9780191007347
