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Let G be any connected (undirected) graph. If C is a set of edges forming a circuit in G and K is a set of

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Let G be any connected (undirected) graph. If C is a set of edges forming a circuit in G and K is a set of edges forming a cutset, show that C and K must have an even number of edges in common (possibly zero). Reminder: A cutset K is a set of edges required to disconnect G into a two-component graph G-K (no vertices are removed)

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