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Let g(x)= x 3 - 6x 2 + 9x. Use the bisection method to find a value of x, to an accuracy of 0.05, such

Let g(x)= x3- 6x2 + 9x. Use the bisection method to find a value of x, to an accuracy of 0.05, such that g(x)=1. (If "a" is the exact solution, then any value x such that |x-a| 0.05 is said to have an accuracy of 0.05)

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