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Let HI) = $3 + 5:2 + 11: 1162. A solution to f[$] = I} can be found between :I: = 3 and :1: =

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Let HI) = $3 + 5:2 + 11: 1162. A solution to f[$] = I} can be found between :I: = 3 and :1: = 9. The line tangent to the graph of y 2 x) at :1: = 3 will have equation 1: = C] An approximate solution to x) 2 U can be found at $1 = The line tangent to the graph of y : at) at 2: = :1 will have equation '3; : (Use the value of :1 you just found} This suggests. that an approximate solution to x) 2 U can be found at $2 =

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