Let I(t) = t - 4t + tand y(t) = t - 3t + 3At t = 1.x(1) =y(1) =dx/dt |t=1 =dy/dt |t=1 =dy/dt |t=1=

Let I(t) = t³ - 4t² + tand y(t) = t² - 3t + 3At t = 1.x(1) =y(1) =dx/dt |t=1 =dy/dt |t=1 =dy/dt |t=1= tangent slope =speed (1) =