Let us assume now that the two species are totally immiscible in the liquid phase. Show that the equilibrium pressure equation simplifies to P* = psat + psat Toluene (1) and Water (2) are essentially immiscible as liquids. What is the three-phase equilibrium pressure (in kPa) if the temperature is 25 C? What is the gas phase composition? With the same mixture of Toluene (1) and Water (2), assume the pressure is 101.33 kPa. What is the three-phase equilibrium temperature in C and the gas phase composition? (Accuracy of 1C is acceptable in your answer for the equilibrium temperature) The vapor mixture with mole fraction y = 0.2 is cooled at constant pressure 101.33 kPa until the dew-point. Determine the dew-point temperature and the composition of the first drops of liquid.