Levi-Strauss Co manufactures clothing.The quality control department measures weekly values of different suppliers for the percentage difference of waste between the layout on the computer and the actual waste when the clothing is made (called run-up).The data is in the following table, and there are some negative values because sometimes the supplier is able to layout the pattern better than the computer ("Waste run up," 2013).

Table #11.3.3: Run-ups for Different Plants Making Levi Strauss Clothing

Plant 1 Plant 2 Plant 3 Plant 4 Plant 5

1.2 16.4 12.1 11.5 24

10.1 -6 9.7 10.2 -3.7

-2 -11.6 7.4 3.8 8.2

1.5 -1.3 -2.1 8.3 9.2

-3 4 10.1 6.6 -9.3

-0.7 17 4.7 10.2 8

3.2 3.8 4.6 8.8 15.8

2.7 4.3 3.9 2.7 22.3

-3.2 10.4 3.6 5.1 3.1

-1.7 4.2 9.6 11.2 16.8

2.4 8.5 9.8 5.9 11.3

0.3 6.3 6.5 13 12.3

35. 9 5.7 6.8 16.9

-0.8 7.1 5.1 14.5

19.4 4.3 3.4 5.2

2.8 19.7 -0.8 7.3

13 3 -3.9 7.1

42.7 7.6 0.9 3.4

1.4 70.2 1.5 0.7

3 8.5

2.4 6

1.3 2.9

Do the data show that there is a difference between some of the suppliers?Test at the 1% level

**********************************************************************

Letx₁= percentage difference of waste between the layout on the computer and the actual waste when the clothing is made (called run-up) from plant 1

Letx₂= percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 2

Letx₃= percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 3

Letx₄= percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 4

Letx₅= percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 5

Let₁= mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 1

Let₂= mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 2

Let₃= mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 3

Let₄= mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 4

Let₅= mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 5

(i)Which of the following statements correctly defines the null hypothesisH_O?

A.All five mean percentage differences are equal

B.Two of the mean percentage differences are not equal

C.At least four of the mean percentage differences are equal

D. At least two of the mean percentage differences are not equal

Let₁= mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 1

Let₂= mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 2

Let₃= mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 3

Let₄= mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 4

Let₅= mean percentage difference of waste between the layout on the computer and the actual waste of run-up from plant 5

(ii)Which of the following statements correctly defines the alternative hypothesisH_A?

A.All five mean percentage differences are equal

B.Two of the mean percentage differences are not equal

C.At least four of the mean percentage differences are equal

D.At least two of the mean percentage differences are not equal

(iii)Enter the level of significanceused for this test:

(iv)Calculate sample mean and sample standard deviation for Plant 1 sample

(v)Calculate sample mean and sample standard deviation for Plant 2 sample

(vi)Calculate sample mean and sample standard deviation for Plant 3 sample

(vii)Calculate sample mean and sample standard deviation for Plant 4 sample

(viii)Calculate sample mean and sample standard deviation for Plant 5 sample

(ix)Using technology, determineFratio test statistic and corresponding p-value.

(x)Comparing p-value andvalue, which is the correct decision to make for this hypothesis test?

A.RejectH_o

B.Fail to rejectH_o

C.AcceptH_o

D.AcceptH_A

(xi)Select the statement that most correctly interprets the result of this test:

A.The result is not statistically significant at .01 level of significance.Sufficient evidence exists to support the claim that there is a difference between some of the suppliers.

B.The result is statistically significant at .01 level of significance.There is not enough evidence to support the claim that there is a difference between some of the suppliers.

C.The result is statistically significant at .01 level of significance.Sufficient evidence exists to support the claim that there is a difference between some of the suppliers.

D.The result is not statistically significant at .01 level of significance.There is not enough evidence to support the claimthat there is a difference between some of the suppliers.