Line p contains point (6, -5) and is perpendicular to line q. The equation for line q is y = 3x + 5.

1) Write an equation for line p.

2) find the slope of line q

3) find the slope of line p (write the negative reciprocal of the slope you found in #2)

4) use the point given for line p and the slope you found in #3 to write an equation for line p in point-slope form: y-y₁=m(x-x₁)

5) use your equation from #4 to write an equation for line p in slope-intercept form:y=mx + b.

Please show as much work as you can so that I can understand how you got the answers. thank you