Question
Listed below are systolic blood pressure measurements (in mm Hg) obtained from the same woman. Find the regression equation, letting the right arm blood pressure
Listed below are systolic blood pressure measurements (in mm Hg) obtained from the same woman. Find the regression equation, letting the right arm blood pressure be the predictor (x) variable. Find the best predicted systolic blood pressure in the left arm given that the systolic blood pressure in the right arm is 95 mm Hg. Use a significance level of
0.05.
Right Arm | 101 | 100 | 94 | 80 | 79 | |
---|---|---|---|---|---|---|
Left Arm | 174 | 168 | 150 | 149 | 147 |
The critical values of the Pearson correlation coefficient r
n | =0.05 | =0.01 | NOTE: To test H0: =0 against H1: 0, reject H0 if the absolute value of r is greater than the critical value in the table. |
---|---|---|---|
4 | 0.950 | 0.990 | |
5 | 0.878 | 0.959 | |
6 | 0.811 | 0.917 | |
7 | 0.754 | 0.875 | |
8 | 0.707 | 0.834 | |
9 | 0.666 | 0.798 | |
10 | 0.632 | 0.765 | |
11 | 0.602 | 0.735 | |
12 | 0.576 | 0.708 | |
13 | 0.553 | 0.684 | |
14 | 0.532 | 0.661 | |
15 | 0.514 | 0.641 | |
16 | 0.497 | 0.623 | |
17 | 0.482 | 0.606 | |
18 | 0.468 | 0.590 | |
19 | 0.456 | 0.575 | |
20 | 0.444 | 0.561 | |
25 | 0.396 | 0.505 | |
30 | 0.361 | 0.463 | |
35 | 0.335 | 0.430 | |
40 | 0.312 | 0.402 | |
45 | 0.294 | 0.378 | |
50 | 0.279 | 0.361 | |
60 | 0.254 | 0.330 | |
70 | 0.236 | 0.305 | |
80 | 0.220 | 0.286 | |
90 | 0.207 | 0.269 | |
100 | 0.196 | 0.256 |
QUESTIONS:
1. The regression equation is? y=____+_______x. (Round to one decimal place as needed.)
2. Given that the systolic blood pressure in the right arm is 90 mm Hg, the best predicted systolic blood pressure in the left arm is __________________ mm Hg?
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