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Local Maximum or Minimum on an Interval f(x) Interval Endpoints -2x + 9x + 4 -1 x 5 (-1)- 1(5)= -x-6x-3 4 x 8
Local Maximum or Minimum on an Interval f(x) Interval Endpoints -2x + 9x + 4 -1 x 5 (-1)- 1(5)= -x-6x-3 4 x 8 (4)- 1(8)= x + 2x+16 x+2 (0) = O x 1 4 f(14) = (-3)= 3x4 4x-36x + 20 -3 x 4 f(4) = Sketch:
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