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lodine and bromine react to form IBr. At 184.4C, the overall reaction proceeds according to the equation I2(g) + Br2(g) = 2 IBr(g) Kp =
lodine and bromine react to form IBr. At 184.4C, the overall reaction proceeds according to the equation I2(g) + Br2(g) = 2 IBr(g) Kp = 1.2 x 102 If you begin the reaction with 7.4 g of I2 vapour and 6.3 g of Br2 vapour in a 1.00-L container, what is the partial pressure of IBr at equilibrium? What is the concentration of I2?
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