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log log( 1 + ? Sustituyendo valores en la formula anterior, tenemos: 2? log ?????????? ??? ? log(1 + 0.006904109589 log( 2 7 = logl

log log( 1 + ? Sustituyendo valores en la formula anterior, tenemos: 2? log ?????????? ??? "?" log(1 + 0.006904109589 log( 2 7 = logl 1+ 0.006904109589 ? = 100.742494 = 101 ???????? ?? 28 21?? ? = 7.748 7h

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