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LogPOP - Coefficient = 1.066, t-stat 14.401 and standard error = 0.074 At 5% significance: N-K-1 = 160-2-1 = 157 degrees of freedom, which is
LogPOP - Coefficient = 1.066, t-stat 14.401 and standard error = 0.074
At 5% significance:
N-K-1 = 160-2-1 = 157 degrees of freedom, which is 1.975189.
How do you prove the coefficient LogPOP is greater than 1 at 5% significance?
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