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SOLUTION:

A 1.50 ?? snowball is fired from a cliff 12.5 ? high. The snowball's initial velocity is 14.0 ?/?, directed 41.0 above the horizontal. Using conservation of mechanical energy, calculate the speed of the snowball as it reaches the ground below the cliff.

4G 1 1 12:35 0 0 Von 73.9 LTE2 KB/S 74 4. Given : m = 1.5kg h = n.sm Vo = 14-0 m/j 9 = 9.8 m/s ? 0 = 41.0. Required : Vr = ? Solution : 2 [ might tivo' = = my ] 2gh + Vo ? = vy ? Vf = Voz + 2 gh VF = ( 19 . on/ 1 ) 2 + 2 ( 9-8 p / 57 )( 12 . Im) E\f