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Lucky Lonnie has a loaded die that lands with the following probabilities: Die shows: 1 2 3 4 5 6 Probability 1/4 1/6 1/8

 

Lucky Lonnie has a loaded die that lands with the following probabilities: Die shows: 1 2 3 4 5 6 Probability 1/4 1/6 1/8 1/6 1/8 1/6 What is the expected value for the game in #1 if Lonnie uses his 'special' die? Is the game fair (assuming it still costs $2 to play)?

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