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m = 0.451 kg of methanol in atmospheric pressure is heated with an electric heater from Ti = 23.2 .C to its boiling point. After

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m = 0.451 kg of methanol in atmospheric pressure is heated with an electric heater from Ti = 23.2 .C to its boiling point. After the heating my = 0.21 kg of the methanol is vaporized. Heating and vaporizing takes t = 498.27 s with n = 0.98 heater's efficiency. What is the volume of methanol? V = m3 Your last answer was interpreted as follows: 1 What is the energy required for heating? Eh KJ Your last answer was interpreted as follow . 1 What is the energy required for vaporizing? E. = KJ Your last answer was interpreted as follows: 1 What is the power of the heater? P = 1 kW rated as follows: 1What is the electr. energy needed for heating and vaporizing? E. KJ Your last answer was interpreted as follows: 1

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